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$No. of solutions of y = \sin (x + 1), y = \sin x in [- 2 π, 2 π]$

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detailed solution

Correct option is B

from the graph no. of solutions = 4

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No. of solutions of y=sin(x+1), y=sinx in [-2π,2π]

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$No. of solutions of y = \sin (x + 1), y = \sin x in [- 2 π, 2 π]$