For non-zero vectors a→,b→ and c→,|(a→×b→)⋅c→|=|a→||b→∥c→| holds if and only if
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
a→⋅b→=0,b→⋅c→=0
b
b→⋅c→=0,c→⋅a→=0
c
c→⋅a→=0,a→⋅b→=0
d
a→⋅b→=b→⋅c→=c→⋅a→=0
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
|(a→×b→)⋅c→|=|a→||b→||c→| or ∥a→||b→|sinθn^⋅c→|=|a→||b→||c→| or |a→||b→||c→||sinθcosα|=|a→||b→||c→| or |sinθ∥cosα|=1⇒ θ=π/2 and α=0⇒ a→⊥b→ and c→∥n^ or perpendicular to both a→ and b→. ⇒ a→⋅b→=b→⋅c→=c→⋅a→=0