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Q.

For non-zero vectors a→,b→ and c→,|(a→×b→)⋅c→|=|a→||b→∥c→| holds if and only if

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a

a→⋅b→=0,b→⋅c→=0

b

b→⋅c→=0,c→⋅a→=0

c

c→⋅a→=0,a→⋅b→=0

d

a→⋅b→=b→⋅c→=c→⋅a→=0

answer is D.

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Detailed Solution

|(a→×b→)⋅c→|=|a→||b→||c→| or  ∥a→||b→|sin⁡θn^⋅c→|=|a→||b→||c→| or  |a→||b→||c→||sin⁡θcos⁡α|=|a→||b→||c→| or  |sin⁡θ∥cos⁡α|=1⇒ θ=π/2 and α=0⇒ a→⊥b→ and c→∥n^ or perpendicular to both a→ and b→. ⇒ a→⋅b→=b→⋅c→=c→⋅a→=0
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