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The normal to the curve $2 x^{2} + y^{2} = 12$ at the point (2,2) cuts the curve again at

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(−229,−29)

(229,29)

(-2,2)

None of these

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detailed solution

Correct option is A

2x2+y2=12 or dydx=−2xy Slope of normal at point A(2,2) is12 Also, point B(−229,−29) lies on the curve and slope of AB is 2−(−2/9)2−(−22/9)=12 Hence, the normal meets the curve again at point (−229,−29)

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The normal to the curve 2x2+y2=12 at the point (2,2) cuts the curve again at

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The normal to the curve $2 x^{2} + y^{2} = 12$ at the point (2,2) cuts the curve again at