Questions
The normal at the point (3, 4) on a circle at the point (-1,-2). The equation of the circle, is
a
x2+y2+2x−2y−13=0
b
x2+y2−2x−2y−11=0
c
x2+y2−2x+2y+12=0
d
x2+y2−2x−2y+14=0
detailed solution
Correct option is B
The normal at P (3, 4) cuts the circle again at Q (-1, - 2). Therefore, PQ is a diameter of the circle. Hence, its equation is(x−3)(x+1)+(y−4)(y+2)=0or x2+y2−2x−2y−11=0Talk to our academic expert!
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For a circle two diameters are
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