The normal at the point (3, 4) on a circle at the point (-1,-2). The equation of the circle, is

The normal at P (3, 4) cuts the circle again at  Q (-1, - 2). Therefore, PQ is a diameter of the circle. Hence, its equation is(x−3)(x+1)+(y−4)(y+2)=0or x2+y2−2x−2y−11=0