Q.
The normal at a point P on the ellipse x2+4y2=16 meets the x -axis at Q . If M is the midpoint of the line segment PQ , then the locus of M intersects the latus rectums of the given ellipse at points
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a
(±(35)/2,±2/7)
b
(±(35)/2,±19/7)
c
(±23,±1/7)
d
(±23,±43/7)
answer is C.
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Detailed Solution
Normal at P is given by 4xsecϕ−2ycosecϕ=12∴Q≡(3cosϕ,0) Let mid-point of PQ be M(α,β) . ∴α=3cosϕ+4cosϕ2=72cosϕ or cosϕ=27α and β=sinϕ Using cos2ϕ+sin2ϕ=1 , we have 449α2+β2=1 or 449x2+y2=1----(1) Now, the latus rectum to above ellipse is x=±23-----(2) Solving (1) and (2), we have 4849+y2=1 or y=±17 The points of intersection are (±23,±1/7) .
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