Normal at a point P on the parabola y2=4ax meetsthe axis at Q such that the distance of Q  from thefocus of the parabola is 10a. The coordinates of Pare:

Equation of the normal at Pat2,2at to the parabolay2=4ax is y=−tx+2at+at3 which meets theaxis y=0  at x=a2+t2. So coordinates of Q area2+t2,0. Focus is  S(a,0)QS=2a+at2−a=a1+k2=10a⇒t2=9So the required coordinates are (9a,±6a).