The number of common tangents that can be drawn to the circle x2+y2−4x−6y−3=0 and x2+y2+2x+2y+1=0 is
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answer is 3.
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Detailed Solution
The two circles are x2+y2−4x−6y−3=0 and x2+y2+2x+2y+1=0. The coordinates of the centres and radii are:Centres: C1(2,3) C2(−1,−1)Radii: r1=4 r2=1Clearly C1C2=5=r1+r2Therefore, there are 3 common tangents to the given circles