The number of common tangents to the circles x2+y2−4x−6y−12=0 and x2+y2+6x+18y+26=0, is
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a
3
b
4
c
1
d
2
answer is A.
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Detailed Solution
The coordinates of the centres and radii of the given circles are: C1:(2,3) C2:(−3,−9)r1:5 r2:8we find that C1C2=13=r1+r2 So, the two circles touch each other externally. Hence, there are 3 common tangents.