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$The number of common tangents of the circles (x + 3)^{2} + (y - 2)^{2} = 49 and$ $(x - 2)^{2} + (y + 1)^{2} = 4 is$

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Correct option is B

Given circles are (x+3)2+(y-2)2=49 and (x-2)2+(y+1)2=4 The given circles have centre at C1(-2,2),C2(2,-1) and redii r1=7,r2=2 Now C1C2=(2+2)2+(-1-2)2=16+9=5=r1−r2 ∴ given circles touch internally. ⇒there is only one common tangent

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The number of common tangents of the circles (x+3)2+(y-2)2=49 and (x-2)2+(y+1)2=4 is

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$The number of common tangents of the circles (x + 3)^{2} + (y - 2)^{2} = 49 and$ $(x - 2)^{2} + (y + 1)^{2} = 4 is$