The number of common tangents of the circles (x+3)2+(y-2)2=49 and (x-2)2+(y+1)2=4 is

Given circles are (x+3)2+(y-2)2=49 and (x-2)2+(y+1)2=4 The given circles have centre at C1(-2,2),C2(2,-1) and redii r1=7,r2=2 Now C1C2=(2+2)2+(-1-2)2=16+9=5=r1−r2 ∴ given circles touch internally. ⇒there is only one common tangent