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Q.

The number of complex numbers satisfying z¯=iz2 is

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a

1

b

2

c

3

d

4

answer is D.

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Detailed Solution

|z¯|=iz2⇒|z|=|z|2⇒          |z|=0  or  |z|=1.If |z|=0, then  z=0If |z|=1, we get ⁡z¯=1/z so that the equation becomes  1/z=iz2or                                z3=−i=i3⇒z=i,iω,iω2where ω(≠1) ) is a cube root of unity
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The number of complex numbers satisfying z¯=iz2 is