The number of complex numbers satisfying z¯=iz2 is
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a
1
b
2
c
3
d
4
answer is D.
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Detailed Solution
|z¯|=iz2⇒|z|=|z|2⇒ |z|=0 or |z|=1.If |z|=0, then z=0If |z|=1, we get z¯=1/z so that the equation becomes 1/z=iz2or z3=−i=i3⇒z=i,iω,iω2where ω(≠1) ) is a cube root of unity