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The number of complex numbers satisfying $\bar{z} = i z^{2}$ is

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Correct option is D

|z¯|=iz2⇒|z|=|z|2⇒ |z|=0 or |z|=1.If |z|=0, then z=0If |z|=1, we get ⁡z¯=1/z so that the equation becomes 1/z=iz2or z3=−i=i3⇒z=i,iω,iω2where ω(≠1) ) is a cube root of unity

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The number of complex numbers satisfying z¯=iz2 is

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The number of complex numbers satisfying $\bar{z} = i z^{2}$ is