Q.
Number of complex numbers such that |z|=1 and |z=1−2z is
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a
0
b
1
c
2
d
infinite
answer is A.
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Detailed Solution
|z|=1⇒zz=1 Therefore z=1−2z ⇒ z=1−2z ⇒ z2−z+2=0⇒ z=1±7i2 but than, |z|≠1
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