Q.

Number of complex numbers such that |z|=1 and |z=1−2z is

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a

0

b

1

c

2

d

infinite

answer is A.

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Detailed Solution

|z|=1⇒zz=1 Therefore  z=1−2z ⇒ z=1−2z ⇒ z2−z+2=0⇒ z=1±7i2 but than, |z|≠1
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