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The number of different 7 digit numbers that can be written using only the three digits 1, 2 and 3 with the condition that the digit 2 occurs twice in each number is

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a
7P2 22
b
7C2 25
c
7C2 55
d
None of these

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detailed solution

Correct option is B

Other than 2, remaining five places are to be filled by 1 and 3∴ number of ways for five places = 2 × 2 × 2 × 2 × 2 = 25For 2, selecting 2 places out of 7=7C2∴ Required number of ways =7C2⋅25.


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