Questions
The number of different 7 digit numbers that can be written using only the three digits 1, 2 and 3 with the condition that the digit 2 occurs twice in each number is
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a
7P225
b
7C225
c
7C252
d
None of these
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Correct option is B
Other than 2, remaining five places are to be filled by by 1 and 3∴ number of ways for five places = 2 × 2 × 2 × 2 × 2 = 25For 2, selecting 2 places out of 7=7C2∴ Required no. of ways =7C2⋅25.Similar Questions
is equal to
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