The number of different seven digit numbers that can be written using only the three digits 1, 2 and 3 with the condition that the digit 2 occurs twice in each number is
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a
7P22
b
7C225
c
7C252
d
None of these
answer is B.
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Detailed Solution
Other than 2, remaining five places can be filled by 1 and 3 for each place. The number of ways for five places2×2×2×2×2=25For 2, selecting 2 places out of 7 is 7C2. Hence, for required number of ways is 7C2×25