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The number of 9 digit numbers which have all distinct digits, is

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a
10!
b
9!
c
8(9)!
d
10! -9!

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detailed solution

Correct option is D

The required number of ways= The number of ways of permuting nine digits out of ten digits 0, 1, 2, …, 9– The number of ways of permuting nine digits out of nine digits 1, 2, …, 9=10P9−9P9=10!1!−9!=10!−9!


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