The number of 5 digited numbers that can be formed using the digits 0, 1, 2, 3, 4, 5 that are divisible by 6 when repetition is not allowed is

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148

180

108

answer is D.

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Detailed Solution

The no of numbers using 1,2,3,4,5 which are even is 2×4! The no of numbers using0,1,2,3,4,5 which are even is4!+2(4!−3!) =2×4!+4!+2(4!−3!)=108

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