The number of distinct real roots of the
equation
(x+3)4+(x+5)4=16 (1)
is
1
2
3
4
Put x + 4 = t, so that (1) becomes
(t−1)4+(t+1)4=16⇒ 2t4+6t2+1=16⇒ t4+6t2−7=0⇒ t2=1,−7⇒t=±1,7i
Thus, the equation (1) has two real roots.