Number of distinct real solutions of the equation x2+xx−12=8 is

x2+xx−12=8⇒x+xx−12−2xxx−1=8⇒x2-x+xx-12−2x2x−1−8=0⇒ x2x−12−2x2x−1−8=0x2x−1=t⇒t2−2t−8=0⇒t=4,t=−2put x2x−1=4⇒x2−4x+4=0⇒x=2 Put x2x−1=−2⇒x2+2x=2⇒x+12=3⇒ x+1=±3⇒ x=±3−1