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The number of divisors of 240 which are of the form , is
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a
4
b
8
c
10
d
3
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Correct option is A
We have,4m+2 and 240=24×3×5Therefore, in any divisor of the form 4m + 2, number 2 must occur exactly once. Hence, the number of divisors of the form 4m + 2 is1X (1 + 1) (1 + 1) = 4Similar Questions
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