The number of divisors of 240 which are of the form 4m + 2, is

We have,4m+2 and 240=24×3×5Therefore, in any divisor of the form 4m + 2, number 2 must occur exactly once. Hence, the number of divisors of the form 4m + 2 is1X (1 + 1) (1 + 1) = 4