Q.

a) The number of elements in the range of a constant function b) If f(x)=ax5+bx3+cx+d  is an odd function, then the value of  d isc) If f:R →R defined byf(x)=3x–4 , then f–1(5)= d) If f:R+→R  such thatf(x)=log5x , then f–1(-1)= Then  arrange the above values in ascending order

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

a, b, c, d

b

b, a, c, d

c

b, a, d, c

d

b, d, a, c

answer is D.

(Unlock A.I Detailed Solution for FREE)

Detailed Solution

(a) a = 1 (b) d = 0             (c) f−1x=x+y5 ⇒f−1(5)=3             (d) f−1(x)=5x⇒f−1(−1)=15                 b, d, a, c
Watch 3-min video & get full concept clarity
Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Online Course for IIT JEE
Best Online Course for NEET
Best Online Course for CBSE
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Online Course for IIT JEE
Best Online Course for NEET
Best Online Course for CBSE
whats app icon
a) The number of elements in the range of a constant function b) If f(x)=ax5+bx3+cx+d  is an odd function, then the value of  d isc) If f:R →R defined byf(x)=3x–4 , then f–1(5)= d) If f:R+→R  such thatf(x)=log5x , then f–1(-1)= Then  arrange the above values in ascending order