The number of even numbers greater than 100 that can be formed by the digits 0, 1, 2, 3 (no digit being repeated) is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
20
b
30
c
40
d
None of these
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
The numbers are of three or four digits.To find the number of even numbers of three digits—The unit’s place must be filled by 0 or 2.∴ The number of even numbers of three digits (having or not having 0 in hundred’s place) =2P1×3P2.But the number of even numbers of three digits having 0 in hundred’s place =2P1 (∵ unit’s place is naturally filled by 2 and ten’s place by one of 1 and 3).∴ The number of even numbers of three digits=2P1×3P2−2P1 (1)Similarly, the number of even numbers of four digits=2P1×3P3−2P2 (2)Adding (1) and (2), we get the number of even numbers greater than 100= 2P1×3P2−2P1+ 2P1×3P3−2P2=2×3×2−2+2×3×2×1−2×1=20