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Q.

The number of five digit numbers that contain 7 exactly once is

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a

(41)93

b

(37)93

c

(7)94

d

(41)94

answer is A.

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Detailed Solution

When 7 is right in the beginning, the number of numbers = 94 and when 7 is not in the beginning, the number of numbers is (C1   4) (8) (93)∴ Required number of numbers    =94+ 4C1(8)93=(41)93
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