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 The number of five-digit numbers that contain 7 exactly once is

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a
(41) 93
b
(37) 93
c
(7) 94
d
(41) 94

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detailed solution

Correct option is A

If 7 is used at first place, the number of numbers is 94 and for any other four places it is 4×8 x 93.the total number of ways = 93(9+32)=41(93)


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