Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

The number of four digit numbers that can be formed from the digits 0, 1, 2, 3, 4, 5 with at least one digit repeated is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

420

b

560

c

780

d

None of these

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

The thousand’s place cannot be filled by O. So the number of ways to fill the thousands’s place = 5.The remaining three places can be filled by six digits in 63 ways, as digits can be repeated.∴ The number of four digit numbers= 5 × 63 = 1080.                         (1)Now, the number of numbers of four digits that do not contain any repeated digit =5P1×5P3 {∵ thousand’s place is to be filled by one of 1, 2, 3, 4, 5 and the remaining three places are to be filled by three of the remaining five digits including 0}. But (1) contains numbers which contain no repeated digits as well as those which contain at least one repeated digit.∴ The number of four digit numbers which contain at least one repeated digit =1080−5P1×5P3= 1080 – 5 × 5 × 4 × 3 = 780.
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
personalised 1:1 online tutoring