Combinations

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Question

Number of four-digit positive integers if the product of their digits is divisible by 3 is.

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Solution

Total number of 4 digited
$+ ve integer = 9 \times 10^{3}$
$Product will be divisible by 3, if atleast one digit is 0 or 3 or 6 or 9$
$∴ an s = 9 \times 10^{3} - 6^{4} = 7704$

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