Questions
Number of identical terms in the sequence 2, 5, 8,11, ... upto 100 terms and 3, 5, 7, 9, 11, ... upto 100 terms, are
detailed solution
Correct option is B
Common terms are 5, 11, 17, …….. Tn=5+(n−1)6=6n−1100th term of the first sequence =2+(100-1)3=299and 100th term of the second sequence =3+(100-1)2=201 201>6n−1⇒n≤3323⇒ n=33 (∵n∈N)Similar Questions
If and 1 are in A.P, then x is equal to
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