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Number of identical terms in the sequence 2, 5, 8,11, ... upto 100 terms and 3, 5, 7, 9, 11, ... upto 100 terms, are
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a
17
b
33
c
50
d
147
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Correct option is B
Common terms are 5, 11, 17, …….. Tn=5+(n−1)6=6n−1100th term of the first sequence =2+(100-1)3=299and 100th term of the second sequence =3+(100-1)2=201 201>6n−1⇒n≤3323⇒ n=33 (∵n∈N)Similar Questions
If and 1 are in A.P, then x is equal to
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