Number of integer values of n so that sinx(sinx+cosx)=n has at least one solution
0
1
2
3
We have sin2x+sinxcosx=n
⇒1−cos2x2+12sin2x=n
⇒sin2x−cos2x=2n−1
⇒−2≤2n−1≤2 ∵ −2≤sin2x−cos2x≤2
⇒−2+1≤2n≤2+1
⇒−2+12≤n≤2+12 ⇒n=0,1