Number of integers satisfying the inequality, x4−29x2+100≤0 is

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answer is D.

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Detailed Solution

We have x4−29x2+100≤0⇒ x2−4x2−25≤0⇒ 4≤x2≤25⇒ x∈[−5,−2]∪[2,5]Integers satisfying above are ±5,±4,±3,±2So, there are eight integers.

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