Questions
a
4
b
5
c
3
d
1
detailed solution
Correct option is D
We have x−6−10−x≥1 We must have x≥6 and x≤10 Then x−6≥1+10−x Squaring given inequality, x−6≥1+10−x+210−x⇒2x−17≥210−xClearly LHS must be positive.∴ x≥172so, we have 4x2+289−68x≥4(10−x)⇒4x2−64x+249≥0⇒x2−16x+2494≥0⇒(x−8)2−722≥0⇒ x−8−72x−8+72≥0From the sign scheme, x∈[(16+7)/2,10]Talk to our academic expert!
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