Q.

The number of integers x, y, z, w such that x + y + z + w = 20 and x, y, z, w ≥ – 1, is

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a

24C3

b

25C3

c

26C3

d

27C3

answer is D.

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Detailed Solution

Put x=a−1,y=b−1,z=c−1,w=d−1then a,b,c,d≥0 and (a−1)+(b−1)+(c−1)+(d−1)=20⇒ a+b+c+d=24The number of non-negative integral solutions of this equationis 24+4−1C4−1=27C3
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