Number of integral values of k 7cosx+5sinx=2k+1 for which the equation has solution
We have −a2+b2≤acosθ+bsinθ≤a2+b2
⇒−74≤7cosx+5sinx≤74
⇒−74≤2k+1≤74
⇒k=−4,−3,−2,−1,0,1,2,3