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Number of integral values of ‘a’ satisfy the equation ${[\sin x]}^{2} + \sin x - 2 a = 0$ is (where [.] denotes G.I.F)

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Correct option is B

We have 2a=sinx2+sinx∵a∈I⇒sinx∈I⇒sinx=sinx∴2a=sinxsinx+1 and sinx=−1 or 0 or 1⇒2a=0 or 2⇒a=0 or 1

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Number of integral values of ‘a’ satisfy the equation sinx2+sinx−2a=0is (where [.] denotes G.I.F)

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Number of integral values of ‘a’ satisfy the equation ${[\sin x]}^{2} + \sin x - 2 a = 0$ is (where [.] denotes G.I.F)