The number of integral value(s) of a so that the graph of y=16x2+8(a+5)x−7a−5 is always above the x-axis is

see full answer

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

answer is 12.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

We have 16x2+8(a+5)x−(7a+5)>0,∀x∈RSo, discriminant must be negative. Now, Discriminant =D=64(a+5)2+7a+5 As D<0⇒a2+17a+30<0⇒(a+15)(a+2)<0∴−15

Watch 3-min video & get full concept clarity