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Number of integral values of x satisfying the inequality $\frac{x^{2} + 6 x - 7}{| x + 2 | | x + 3 |} < 0$ is

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Correct option is A

We have x2+6x−7|x+2||x+3|<0Clearly, x≠−2,−3Now, x2+6x−7<0⇒ (x+7)(x−1)<0⇒ x∈(−7,1)−{−3,−2}So, integers are {−6,−5,−4,−1,0}

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Observer the following lists

List - I

Functions

I. $f (x) = \sqrt{\sin^{- 1} (\log_{2} x)}$

II. $g (x) = \sqrt{\cos (\sin x)}$

III. $h (x) = \sin^{- 1} (\frac{1 + x^{2}}{2 x})$

IV. f(x) = g(x) + h(x)

List - II

Domain

a) {-1, 1}

b) {1}

c) {-1}

d) [1, 2]

e) R

The correct matching of List I to List II is

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Number of integral values of x satisfying the inequality x2+6x−7|x+2||x+3|<0 is

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Number of integral values of x satisfying the inequality $\frac{x^{2} + 6 x - 7}{| x + 2 | | x + 3 |} < 0$ is