Number of integral values of x satisfying the inequation  xx+2≤1|x| is

x|x|x+2≤1x|x|−x−2x+2≤0 Case I: x∈[0,∞) x2−x−2x+2≤0⇒ (x−2)(x+1)x+2≤0 ⇒ 0≤x≤2         ∵x∈[0,∞)i.e., integral values of x are 0, 1 , 2. Case II: x∈(−∞,0) −x2−x−2x+2≤0⇒ −2