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The number of integral values of x satisfying $\sqrt{- x^{2} + 10 x - 16} < x - 2 is$

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Correct option is D

−x2+10x−160⇒ x2−7x+10>0⇒x>5 or x<2---(2) From (1) and (2), 5

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The number of integral values of x satisfying −x2+10x−16<x−2 is

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The number of integral values of x satisfying $\sqrt{- x^{2} + 10 x - 16} < x - 2 is$