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The number of lines drawn from the point (4, -5) so that its distance from (-2, 3) will be equal to 12 is

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Correct option is D

If possible, equation of line is y+5=m(x−4)⇒ y−mx+4m+5=0perpendicular distance from (-2,3) is Then 3+2m+4m+51+m2=12⇒ (8+6m)2=1441+m2⇒ 27m2−24m+20=0Here, discriminate < 0 Therefore, no such line possible for real value of m.

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