The number of lines which are equally inclined to the coordinate axes, is k. If k2+eloge6A+13(k)=4k. Thenk−A=

The number of lines which are equally inclined to the coordinate axes is 4Hence, substitute k=4in the equationk2+eloge6A+13(k)=4k16+4A+1=16A=−1Therefore, k−A=4+1=5