Q.

The number of non zero terms in the expansion of (1+32x)9+(1−32x)9 is

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a

9

b

0

c

5

d

10

answer is C.

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Detailed Solution

In the expansion of (1+32x)9+(1−32x)92nd, 4th, 6th, 8th and 10th terms get cancelled.∴ Number of non-zero terms in2[9C0+9C2(32x)2+…+9C8(32x)8] is 5
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The number of non zero terms in the expansion of (1+32x)9+(1−32x)9 is