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The number of non-negative solutions of x1+x2+x3+,,+xnn (where n is positive integer) is

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a
2nCn−1
b
2n−1Cn−1
c
2n+1Cn−1
d
2n−1Cn−1−1

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detailed solution

Correct option is A

In general, we know thatFor the distribution equationx1+x2+x3+…+xn≤nLet required ways = W⇒W=No. of ways of distributing 1 item+No. of ways of distributing 2 items+......+No. of Ways of distributing n items=1+n−1Cn−1+2+n−1Cn−1+…+n+n−1Cn−1=nCn−1+n+1Cn−1+…+2n−1Cn−1= nCn−1+nCn+n+1Cn−1+…+2n−1Cn−1−nCn= n+1Cn+n+1Cn−1+…+2n−1Cn−1−nCn- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -= 2n−1Cn+2n−1Cn−1−nCn=2nCn−nCn∴ W=2nCn−1


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