The number of numbers greater than 106 that can be formed using the digits of the number 2334203, if all the digits of the given number must be used, is

The total number of permutations of the digits of given number is7!2!3!=420But when 0 occupies the first position, the number becomes a six-digit number which are not acceptable, since such a number will become less then 106.The total number of such six-digit numbers is=6!2!3!=60Hence, the required number is 420 – 60 = 360.