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The number of ordered pairs of integers $(x, y)$ satisfying the equation $x^{2} + 6 x + y^{2} = 4$ is

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Correct option is D

x2+6x+y2=4⇒(x+3)2+y2=13⇒(x+3,y)=(±3,±2) or (±2,±3)⇒x=0,y=±2,x=−6,y=±2x=−1,y=±3,x=−5,y=±3

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The number of ordered pairs of integers (x, y) satisfying the equation x2+6x+y2=4 is

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The number of ordered pairs of integers $(x, y)$ satisfying the equation $x^{2} + 6 x + y^{2} = 4$ is