The number of ordered pairs of integers (x, y) satisfying the equation x2+6x+y2=4 is
2
4
6
8
x2+6x+y2=4⇒(x+3)2+y2=13⇒(x+3,y)=(±3,±2) or (±2,±3)⇒x=0,y=±2,x=−6,y=±2x=−1,y=±3,x=−5,y=±3