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The number of ordered pairs such that is a multiple of 5 is
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a
1250
b
2500
c
500
d
625
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Correct option is A
As the last digit of 6m,m∈N is 6,6m+9n will be divisible by 5 if the unit’s digit of 9n is 4 or 9. This is possible when n is odd.∴ required number of ordered pairs = 50 x 25 =1250.Similar Questions
The number of integral solutions of is
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