Number of ordered pairs (x,y) of real numbers satisfying  the equation 2x4−2x2+3y4−3y2+4=7 , is

2x4−2x2+3y4−3y2+4=7⇒ 2x2−12+2y2−322+74=7Now, least value of L.H.S. is 7. Hence, equality holds when x2=1 and y2=32 . ⇒ x=±1 and y=±32Hence, 4 ordered pairs satisfy the equation. These are 1,32,1,−32,−1,32,−1,−32