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The number of ordered triplets of positive integers which are solutions of the equation x + y + z = 100 is

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a
5081
b
6005
c
4851
d
None of these

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detailed solution

Correct option is C

The number of triplets of positive integers which are solutions of x + y + z = 100= Coefficient of x100 in x+x2+x3+…3= Coefficient of x100 in x3(1−x)−3= Coefficient of x100 in x31+3x+6x2+…+(n+1)(n+2)2xn+…=(97+1)(97+2)2=49×99=4851


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