Questions
The number of ordered triplets of positive integers which are solutions of the equation x + y + z = 100 is
detailed solution
Correct option is C
The number of triplets of positive integers which are solutions of x + y + z = 100= Coefficient of x100 in x+x2+x3+…3= Coefficient of x100 in x3(1−x)−3= Coefficient of x100 in x31+3x+6x2+…+(n+1)(n+2)2xn+…=(97+1)(97+2)2=49×99=4851Similar Questions
is equal to
799 666 8865
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