Q.
The number of ordered triplets of positive integers which are solutions of the equation x + y + z = 100 is
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a
5081
b
6005
c
4851
d
None of these
answer is C.
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Detailed Solution
The number of triplets of positive integers which are solutions of x + y + z = 100= Coefficient of x100 in x+x2+x3+…3= Coefficient of x100 in x3(1−x)−3= Coefficient of x100 in x31+3x+6x2+…+(n+1)(n+2)2xn+…=(97+1)(97+2)2=49×99=4851
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