Q.
The number of points in the complex plane that satisfying the conditions |z−2|=2 , z(1−i)+z¯(1+i)=4 , (where i=−1 ) is:
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a
0
b
1
c
2
d
More than 2
answer is C.
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Detailed Solution
∵ Centre of the circle |z−2|=2 is ( 2,0) and it lies on z(1−i)+z¯(1+i)=4 .Hence, given line z(1−i)+z¯(1+i)=4 pass through the center of the circle, i.e., intersect at two points.∴ Number of solutions =2.
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