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Number of points having position vector , where a, b, c ∈ {1, 2, 3, 4, 5} such that 2a + 3b + 5c is divisible by 4 is
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a
140
b
70
c
100
d
None of these
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Correct option is B
4m=2a+3b+5c=2a+(4−1)b+(4+1)c4m=4k+2a+(−1)b+(1)c∴ a = 1, b = even, c = any numbera ≠ 1, b = odd, c = any number∴ Required number = 1 × 2 × 5 × 4 × 3 × 5 = 70Similar Questions
The number of divisors of 240 which are of the form , is
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