Number of points of non-differentiability of the function gx=x2cos24x+x2cos24x+x2sin2⁡4x+x2cos2⁡4x+x2cos2⁡4x in (−50,50) where [x] and {x} denotes the  greatest integer function and fractional part function of x respectively, is equal to

consider, g(x)=x2cos2⁡4x+x2cos2⁡4x+x2cos2⁡4x+x2cos2⁡4x+x2sin2⁡4x=x2+x2cos2⁡4x+cos2⁡4x+x2sin2⁡4x=x2cos2⁡4x+x2sin2⁡4x   (for eg. 2.25=2 and 2.25=0.25 then 2.25+ 2.25 =2.25)=x2 Clearly g(x) is continuous and differentiable ∀x∈ℝNumber of points of non-differentiability is ‘0’Therefore, the correct answer is 0.00.