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Questions  

 Number of positive integers satisfying (x+2)x22x+14+3xx2≥ 0 is

a
0
b
1
c
2
d
3

detailed solution

Correct option is B

(x+2)x2−2x+1−x2+3x−4≥0⇒ (x+2)(x−1)2x2−3x+4≤0 but  x2−3x+4>0∀x∈R  since  ∆ =9-4·1·4=-7<0    ∴ (x+2)(x−1)2≤0⇒ x∈(−∞,−2]∪{1}  therefore only 1 is the positive integral solution

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The solution of x1=(x[x])(x{x})  (where [x]  and {x}  are the integral and fractional part of x ) is :


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