Q.

The number of positive integers which can be formed by any number of digits from 0, 1, 2, 3, 4, 5 but using each digit not more than once in each number are

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a

600

b

1629

c

1630

d

601

answer is C.

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Detailed Solution

One digit  numbers                                =     −→5      ( except 0) Two digited numbers                                 =    −−→5·5=25   ( first blank can be filled in 5 ways (except 0) and the second blank can be                                                                                                                                                                                                filled in P(5,1) ways).  Three digited numbers                             =     −−−→5×P2   5=100 ( first blank can be filled in 5 ways and the remaining 2 blanks can be                                                                                                                  filled in P(5,2) ways.  )   Four digited numbers                              =    −−−−→5.P3   5=300   Five digited numbers                               =   −−−−−→5.P4   5=600   Six digited numbers                                 =    −−−−−−→5.5!=600     Number of ways                                      =1630
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