The number of positive integers which can be formed by any number of digits from 0, 1, 2, 3, 4, 5 but using each digit not more than once in each number are
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a
600
b
1629
c
1630
d
601
answer is C.
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Detailed Solution
One digit numbers = −→5 ( except 0) Two digited numbers = −−→5·5=25 ( first blank can be filled in 5 ways (except 0) and the second blank can be filled in P(5,1) ways). Three digited numbers = −−−→5×P2 5=100 ( first blank can be filled in 5 ways and the remaining 2 blanks can be filled in P(5,2) ways. ) Four digited numbers = −−−−→5.P3 5=300 Five digited numbers = −−−−−→5.P4 5=600 Six digited numbers = −−−−−−→5.5!=600 Number of ways =1630