Q.

The number of positive integers which can be formed by any number of digits from 0, 1, 2, 3, 4, 5 but using each digit not more than once in each number are

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

600

b

1629

c

1630

d

601

answer is C.

(Unlock A.I Detailed Solution for FREE)

Detailed Solution

One digit  numbers                                =     −→5      ( except 0) Two digited numbers                                 =    −−→5·5=25   ( first blank can be filled in 5 ways (except 0) and the second blank can be                                                                                                                                                                                                filled in P(5,1) ways).  Three digited numbers                             =     −−−→5×P2   5=100 ( first blank can be filled in 5 ways and the remaining 2 blanks can be                                                                                                                  filled in P(5,2) ways.  )   Four digited numbers                              =    −−−−→5.P3   5=300   Five digited numbers                               =   −−−−−→5.P4   5=600   Six digited numbers                                 =    −−−−−−→5.5!=600     Number of ways                                      =1630
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon